Why is 3 > 2 > 1 false in JavaScript?

While this is a perfectly valid mathematical comparison, which would usually yield true, programming languages evaluate expressions differently, and JavaScript itself is no different.

We have to split the expression into two parts: first of all, 3 > 2 gets evaluated, which yields true.

3 > 2 === true

Now the rest has to be evaluated: true > 1. This isn’t directly possible, as the types are different so coercion happens under the hood. In case of the greater-than (>) operator, a type hint of number is passed so true is converted to a number.

Number(true) > Number(1)
=> 1 > 1
=> false