Do objects see prototype changes made after they're created?

Do you know what will be the output of this code?

JavaScript

function Dog() {}
Dog.prototype.bark = () => "woof";

const d = new Dog();
Dog.prototype.bark = () => "WOOF";
console.log(d.bark());

Show answer and explanation

The answer is "WOOF".

d doesn’t have its own bark. Each call looks it up on Dog.prototype, which by then holds the new function.

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