Do you know what will be the output of this code? let x = 1; const getX = () => x; x = 2; console.log(getX());

Does a JavaScript closure capture the value or the variable?

Do you know what will be the output of this code?

JavaScript

let x = 1;
const getX = () => x;
x = 2;
console.log(getX());

Show answer and explanation

The answer is 2.

A closure keeps a live reference to the variable, not a snapshot of its value. By the time getX() runs, x is 2.