Do you know what will be the output of this code? function make() { let n = 0; return () => ++n; } const a = make(); const b = make(); a(); a(); console.log(b());

Do two closures from the same function share state?

Do you know what will be the output of this code?

JavaScript

function make() {
  let n = 0;
  return () => ++n;
}

const a = make();
const b = make();
a();
a();
console.log(b());

Show answer and explanation

The answer is 1.

Every call to make() creates a new n. a and b close over different variables, so calling a twice doesn’t affect b.